Let the three numbers in G.P. be \(\frac{a}r,a,ar\).
According to the given conditions,
\(\frac{a}r+a+ar=35\)
a(\(\frac1r+1+r\)) = 35......(i)
Also, (a/r)(a)(ar) = 1000
a3 = 1000
∴ a = 10
Substituting the value of a in (i), we get
Hence, the three numbers in G.P. are 20, 10, 5, or 5, 10, 20.