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If the middle term in the expansion of (x + b/x)6 is 160, find b.

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Here, a = x, b = b/x, n = 6.

Now, n is even.

\(\therefore\) \(\frac{n+2}2=\frac{6+2}2=4\)

\(\therefore\) Middle term is t4, for which r = 3

\(\therefore\) t4 = 160

We have 

\(\therefore\) 160 = b3

\(\therefore\) b = 2

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