Let L1 and L2 be the distances rolled down by the sphere along the corresponding inclines from the same height h.
∴ L1 sin θ1 = L2 sin θ2 = h


Therefore, h being the same, \(V_{CM1}\) = \(V_{CM2}\)

v = u + at
with u = 0 and \(V_{CM1}\) = \(V_{CM2}\), aCM1t1 = aCM2t2.

The sphere will take longer time to roll down from the same height on the plane with smaller inclination.