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+2 votes
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in Straight Lines by (25 points)
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Find the incentre of the triangle whose vertices are (2,3),(−2,−5),(−4,6).

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1 Answer

+1 vote
by (39.1k points)

Let

A = (2,3)

B = (−2,−5)

C = (−4,6)

Now by using straight line formula for two points 

\(\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\) We get,

Now for the incentre of the triangle we get

 = (-1, 2)

Hence the required points of incentre is =(−1, 2)

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