Data : Mass of hydrogen = 4 grams,
V = 16 litres = 16 × 10-3 m3,
T = 273 + 10 = 283 K, M0 = 2 g/mol,
R = 8.314 J/mol.K
Number of moles (n) = \(\frac{mass}{M_0}\) = \(\frac42\) = 2
PV = nRT
∴ P = \(\frac{nRT }V\) = \(\frac{2\times8.314\times283}{16\times10^{-3}}\)
P = 2.941 × 105 N/m2
This is the pressure exerted by the gas.