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Determine the pressure exerted by 4 grams of hydrogen occupying a volume of 16 litres at 10 °C. (R = 8.314 J/mol.K, molar mass of hydrogen = 2 g/mol)

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Data : Mass of hydrogen = 4 grams,

V = 16 litres = 16 × 10-3 m3,

T = 273 + 10 = 283 K, M0 = 2 g/mol,

R = 8.314 J/mol.K

Number of moles (n) = \(\frac{mass}{M_0}\) = \(\frac42\) = 2

PV = nRT 

∴ P = \(\frac{nRT }V\) = \(\frac{2\times8.314\times283}{16\times10^{-3}}\)

P = 2.941 × 105 N/m2

This is the pressure exerted by the gas.

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