Correct Option is (D) \((\frac{\pi}{6})^{\frac{1}{3}} : 1\)
Given, A sphere and cube have same volume
then, \(\frac{4}{3} \pi r^3 = a^3\)
\(a = (\frac{4}{3} \pi)^{\frac{1}{3}} r\)
Heat radiated,
\(\theta = \sigma AT^4\)
\(\frac{\theta _1}{\theta_2} = \frac{4\pi^2}{6a^2}\)
\(\frac{\theta _1}{\theta_2} = \frac{4 \pi r^2}{6[(\frac{4}{3}\pi)^\frac{2}{3}r^2]}\)
\(\frac{\theta _1}{\theta_2} = \frac{2 \pi r^2}{3[(\frac{4 \pi}{3})^\frac{2}{3}r^2]}\)
\(\frac{\theta_1}{\theta_2} = (\frac{\pi}{6})^{\frac{1}{3}} :1\)
\(\theta _1 = \) heat radiated by sphere
\(\theta_2 = \) Heat radiated by cube