Question

The pH of 0.001 N acetic acid solution, which is 10% dissociated, is

(a) 3

(b) 1

(c) 4

(d) 2

Answer 1

Correct option (c) weak electrolytes  

Explanation:

Concentration of acetic acid = 0.001 N for

10% dissociation, the effective concentration of H⁺ is one-tenth of total concentration.

Therefore, effective concentration = 1/10 x 0.001 N

= 0.0001 N

⇒ pH = -log[H⁺] = 4