In an `NPN` transistor the collector current is `10 mA`. If `90%` of electrons reach collector, the emitter current `(i_(E))` and base current `(i_(B))` are given by
A. `I_(E)=1mA,I_(B)=11mA`
B. `I_(E)=11mA,I_(B)=1mA`
C. `I_(E)=-1mA,I_(B)=9mA`
D. `I_(E)=9mA,I_(B)=-1mA`