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A small uniform cylinder floats upright to a depth d in a liquid. If it is depressed slightly and released, find its period of oscillations.

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Consider a cylinder, of length L, area of cross section A and density ρ, floating in a liquid of density σ. If the cylinder floats up to depth d in the liquid, then by the law of floatation, the weight of the cylinder equals the weight of the liquid displaced, i.e.,

ALρg = Adσg 

∴ L = dσ/p … (1)

Let the cylinder be pushed down by a distance y. Then, the weight of the liquid displaced by the cylinder of length y will exert a net upward force on the cylinder :

F = Ayσg, 

which produces an acceleration,

a = \(\frac Fm\) = \(\frac {Ay\sigma g}{AL\rho}\) = \(\frac {\sigma g}{\rho L}\)y = - \(\frac {\sigma g}{\rho (d\sigma/\rho)}\) = - \(\frac gd\)y [from Eq. (1)]

\(\therefore\) Acceleration per unit displacement, |a/y| = \(\frac gd\)

\(\therefore\) period of SHM of the floating cylinder ,

T = \(\frac{2\pi}{ Acceleration \,per \,unit \,displacement,}\) = 2\(\pi\)\(\sqrt{\frac dg}\)

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