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The value of escape velocity on a certain planet is 2km/s. Then the value of orbital speed for a satellite orbiting close to its surface is ___________

(a) 12km/s

(b) 1km/s

(c) √2km/s

(d) 2√2km/s

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Right answer is (c) √2km/s

For explanation: Near earth’s surface,

v0=ve/√2=2/√2=√2 km/s.

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