Question

A body is executing simple harmonic motion. When the displacements from the mean position are 4cm and 5cm, the corresponding velocities of the body are 10cm/sec and 8cm/sec. Thenwhat is the time period of the body?

(a) 2π sec

(b) π/2 sec

(c) π sec

(d) 3π/2 sec

Answer 1

The correct choice is (c) π sec

To explain I would say: T=2π√(((x2)^2-(x1)^2)/((u1)^2-(u2)^2))=2π√((5^2-4^2)/(10^2-8^2))

T=2π√(9/36)=2π×3/6=πsec.