The correct option is (b) The greatest difference between the various oxidation states of bromine is 5.
Explanation:
Thus, during the reaction, bromine is present in four different oxidation states i.e., zero in Br2, + 1 in NaBrO, -1 in NaBr and +5 in NaBrO3. The greatest difference between various oxidation states of bromine is 6 and not 5. On acidification of the final mixture, Br2 is formed and disproportionation of Br2 occurs during the reaction giving BrO-, Br- and BrO3- ions.