Question

The normal meet the parabola y² = 4ax at that point where the abissiae of the point is equal to the ordinate of the point is

(a) (6a, - 9a) 

(b) (-9a, 6a) 

(c) (-6a, 9a) 

(d) (9a, - 6a)

Answer 1

Correct option  (d) (9a, - 6a)

Explanation:

If normal drawn to point (at¹₂,2at₁) of a parabola y²= 4ax = meets at point (at²₂,2at₂) of same parabola 

then, t₂ = -t₁ - 2 / t₁

In question x = y (given)

Because abscissa and ordinate are equal