Evaluate the following limits: lim[√Z+6/Z], (z ∈ -3)

Question

Evaluate the following limits:

 \(\lim\limits_{z\longrightarrow-3} [\frac {√{Z+6}}{Z}]\)

lim[√Z+6/Z], (z ∈ -3)

Answer 1

\(\lim\limits_{z\longrightarrow-3} [\frac {√{Z+6}}{Z}]\) = \(\frac{\lim\limits_{z-3}\sqrt{Z+6}}{Z}\)

= \(\frac {\sqrt {-3+6}}{-3} = \frac {\sqrt3}{-3} = \frac {-1}{\sqrt3} \)