Question

Calculate the length of a seconds pendulum at a place where g = 9.81 m/s² .

Answer 1

Data : T = 2 s, g = 9.81 m/s²

Period of a simple pendulum, T = 2π \(\sqrt{\frac{L}{g}}\)

For a seconds pendulum, 2 = 2π \(\sqrt{\frac{L}{g}}\)

∴ The length of the seconds pendulum,

L = \(\frac{g}{\pi^2}\) = \(\frac{9.81}{(3.142)^2}\) = 0.9937