Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
1.7k views
in Physics by (32.7k points)
closed by

A simple harmonic progressive wave is given by the equation y = 0.1 sin 4π (50t – 0.1 x), in SI units. Find the amplitude, frequency, wavelength and speed of the wave.

1 Answer

+1 vote
by (32.9k points)
selected by
 
Best answer

Data : y = 0.1 sin 4π (50t – 0.1 x) 

= 0.1 sin 2π (100t – 0.2 x)

= 0.1 sin 2π( 100t –\(\frac x5\))

Let us compare this equation with that of a simple harmonic progressive wave.

∴ y = A sin 2π(nt – \(\frac x5\)) = 0.1 sin2π(100t – \(\frac x5\))

Comparing the quantities on both sides, we get,

1. amplitude (A) = 0.1 m 

2. frequency (n) = 100 Hz 

3. wavelength (λ) = 5 m 

4. speed (v) = nλ = 100 × 5 = 500 m/s

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...