Data : y = 0.1 sin 4π (50t – 0.1 x)
= 0.1 sin 2π (100t – 0.2 x)
= 0.1 sin 2π( 100t –\(\frac x5\))
Let us compare this equation with that of a simple harmonic progressive wave.
∴ y = A sin 2π(nt – \(\frac x5\)) = 0.1 sin2π(100t – \(\frac x5\))
Comparing the quantities on both sides, we get,
1. amplitude (A) = 0.1 m
2. frequency (n) = 100 Hz
3. wavelength (λ) = 5 m
4. speed (v) = nλ = 100 × 5 = 500 m/s