Data : y = 0.02 cos (πx) sin (100 πt) m Comparing this equation with
y = 2A cos \((\frac{2\pi x}\lambda)\) sin (2πnt)
we get for either interfering waves,
1. the amplitude, | A | = \(\frac{0.02}2\) = 0.01 m
2. the wavelength, λ = 2 m
3. the time period, T = \(\frac 1n\) = \(\frac 1{50}s\) = 0.02 s
4. the frequency, n = 50 Hz
5. the wave speed = nλ = 50 × 2 = 100 m/s