Let LO and LC be the lengths of a pipe open at both ends and a pipe closed at one end, respectively. Let nO and nC be their corresponding fundamental frequencies. Then, ignoring the end corrections,
nO = \(\frac v{2L_O}\) and nC = \(\frac v{4L_C}\)
where v is the speed of the sound in air.
Given that LO = LC = L (say),
nO = \(\frac v{2L}\) and nO = \(\frac v{4L}\)
∴ nO = 2 \((\frac v{4L})\) = 2nC