Find a relation between x and y such that the point (x, y) is equidistant from the point (3, 6) and (– 3, 4).

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Find a relation between x and y such that the point (x, y) is equidistant from the point (3, 6) and (– 3, 4).

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Answer:
Point (xy) is equidistant from (3, 6) and ( - 3, 4).
x2 + 9 - 6x + y2 + 36 - 12y = x2 + 9 + 6x + y2 + 16 - 8y
36 - 16 = 6x + 6x + 12y - 8y
20 = 12x + 4y
3x + y = 5
3x + y - 5 = 0

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