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Figure (a), (b) and (c) show three cylindrical copper conductors along with their face areas and length. Which of the conductors will have highest resistance and why?

2 Answers

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by (15.2k points)
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Best answer

Considering all the three cylinders one by one and substituting the values in the formula,

(1) For the cylinder in case (a),

\(R = \rho \frac LA\)

(2) For the cylinder in case (b),

\(R = \rho \frac{2L}{A/2} = 4\rho \frac LA\)

(3) For the cylinder in case (c), the resistance is,

\(R = \rho \frac {L/2}{2A} = \rho \frac L{4A}\)

As we compare the three cases, we come to know that the resistance of the cylinder in (b) is maximum as it has twice the length and half the area.

+1 vote
by (266k points)

Hence, Rb >Ra > Rc. Thus, the conductor (b) will have the highest resistance.

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