Considering all the three cylinders one by one and substituting the values in the formula,
(1) For the cylinder in case (a),
\(R = \rho \frac LA\)
(2) For the cylinder in case (b),
\(R = \rho \frac{2L}{A/2} = 4\rho \frac LA\)
(3) For the cylinder in case (c), the resistance is,
\(R = \rho \frac {L/2}{2A} = \rho \frac L{4A}\)
As we compare the three cases, we come to know that the resistance of the cylinder in (b) is maximum as it has twice the length and half the area.