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The cathodic reaction that occurs during corrosion in oxygenated acidic solution is ______

(a) 2H^++2e^-==>H2

(b) 4H^++O2+4e^-==>2H2O

(c) 2H2O+2e^-==>H2+2OH^-

(d) 2H2O+O2+4e^-==>4OH^-

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Correct choice is (b) 4H^++O2+4e^–==>2H2O

The best I can explain: The common hydrogen reduction reaction in corrosion will proceed based on the pH and the amount of oxygen present in the solution. Then oxygenated acidic solution (pH < 7) will react as

4H^++O2+4e^–==>2H2O.

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