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In a parallel RL circuit, 12 A current enters into the resistor R and 16 A current enters into the Inductor L. The total current I the sinusoidal source is ___________

(a) 25 A

(b) 4 A

(c) 20 A

(d) Cannot be determined

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The correct choice is (c) 20 A

The explanation is: Currents in resistance and inductance are out of phase by 90°.

Hence, I = \(I_1^2 + I_2^2\)

Or, I = \([12^2 + 16^2]^{0.5}\)

Or, I = \(\sqrt{144+256} = \sqrt{400}\)

= 20 A.

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