Option 3 is correct
Explanation
Given that the charge on left plate of 10uF capacitor is -30uC. So its right plate will have +30uC charge.This charge will be distributed between two plates of 6uF and 4uF connected in parallel combination. So +30uC charge will be distributed in the ratio of the capcitcapaces of 6uF and 4uF capacitors.
Hence the charge on left plate of 6uF capacitor will be +30×6/(6+4) uC = +18uC.
And its right plate will acquire charge of -18uC.