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The equation \( \left[\begin{matrix} 2 && -2 \\\ 1 && -1 \end{matrix}\right] \left[\begin{matrix} x_1 \\\ x_2 \end{matrix}\right]= \left[ \begin{matrix} 0 \\\ 0 \end{matrix} \right]\) has
1. no solution
2. only one solution \(\left[ \begin{matrix} x_1 \\\ x_2 \end{matrix} \right] = \left[ \begin{matrix} 0 \\\ 0 \end{matrix} \right]\)
3. non-zero unique solution
4. multiple solutions
5.

1 Answer

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Best answer
Correct Answer - Option 4 : multiple solutions

Homogenous system of linear equations:

 

Homogenous equations are the set of equations linear equations that can be written in matrix form as AX = 0.

Where,

A is a matrix of the coefficients and X is the column matrix of the variables.

Theorem:

The system AX = 0 has,

  • Unique solution (zero solution or trivial solution), if the rank of A (ρ(A) is equal to number of variables(n).
  • Infinitely many solutions non-zero solutions, if ρ(A) < n.
  • In this case, if |A| = 0 then the system posses infinitely many non-trivial solutions i.e., non-zero solutions.
  • In this case, if |A| ≠ 0 then the system posses only a trivial solution (i.e., zero solution or unique solution.)
  • If ρ(A) = r, and number of variables = n, then the number of linearly independent solution of AX = 0 is 'n-r' 

 

Calculation:

Given that,

\( \left[\begin{matrix} 2 && -2 \\\ 1 && -1 \end{matrix}\right] \left[\begin{matrix} x_1 \\\ x_2 \end{matrix}\right]= \left[ \begin{matrix} 0 \\\ 0 \end{matrix} \right]\)

⇒ A = \( \left[\begin{matrix} 2 && -2 \\\ 1 && -1 \end{matrix}\right] \)

⇒ |A| = 0

As det A is zero, the rank of the matrix ((ρ (A) =1) < order of the matrix (n = 2).

The given system posses infinitely many non-trivial solutions i.e., non-zero solutions.

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