Question

There are two containers, with one containing 4 Red and 3 Green balls and the other containing 3 Blue and 4 Green balls. One ball is drawn at random from each container. The probability that one of the balls is Red and the other is Blue will be
1. 1/7
2. 9/49
3. 12/49
4. 3/7
5.

Answer 1

Correct Answer - Option 3 : 12/49

Explanation:

Given,

There are 2 containers,

Container 1 has ( 4 Red and 3 Green Balls)

Probability of Red = 4/7

Container 2 has ( 3 Blue and 4 Green Balls)

Probability of being blue = 3/7

One Ball is Drawn from each container Randomly

Probability (One Red & another is Blue) = Probability (first is red & Second is Blue) 

= 4/7 x 3/7

= 12/49