f(x) = \(\frac {3\, sin^2x+2\,cos\,x(1-cos\,2x)}{2(1-cos^2x)}\), for x ≠ 0.
Here, f(0) is not defined.
Consider,
But f(0) is not defined.
∴ f(x) has a removable discontinuity at x = 0.
∴ The extension of the original function is
f(x) = \(\frac {3\, sin^2x+2\,cos\,x(1-cos\,2x)}{2(1-cos^2x)}\), x ≠ 0.
= 7/2, x = 0
∴ f(x) is continuous at x = 0.