Question

If there is a sequence of 5 consecutive integers and the average of first three integers is t then, find the average of all five integers is

1. t + 2
2. t + 1
3. t + 5
4. t

Answer 1

Correct Answer - Option 2 : t + 1

Given:

 We have a sequence of 5 consecutive integers.

The average of the first 3 integers is t.

Calculation:

Let the three consecutives integers be x - 1, x and x + 1 respectively.

The average of three consecutives numbers is

⇒ [(x – 1) + x + (x + 1)]/3

⇒ 3x/3 = x

According to the question, the average of the first three integers is t

We can write x = t

Similarly, the average of all 5 consecutives integers is         

⇒ [(x – 1) + x + (x + 1) + (x + 2) + (x + 3)]/5

⇒ (5x + 5)/5 = x + 1

Earlier we calculated x = t, according to this we can write

x + 1 = t + 1

∴ The average of all five integers is t + 1.