Correct Answer - Option 3 : Rs.900
Calculation:
Total sum borrowed = Rs.38000
Total amount to be paid after 4 years = 38000 × 20 × 4/100 + 38000 = Rs.68400
Let first, second, third and forth installments be Rs.a, Rs.2a, Rs.4a and Rs.6a respectively
⇒ 68400 = a + a × 20 × 3/100 + 2a + 2a × 20 × 2/100 + 4a + 4a × 20 × 1/100 + 6a
⇒ 68400 = 13a + 22a/10
⇒ a = 4500
First installment = Rs.4500
Simple interest for first year = 38000 × 20 × 1/100 = Rs.7600
Amount paid after first year = 38000 - 4500 = Rs.33500
Simple interest for second year = 33500 × 20 × 1/100 = Rs.6700
∴ Required difference = 7600 - 6700 = Rs.900
Simple interest for first year = P × R × 1/100
Simple interest for the second year = (P - first installment) × R × 1/100