Correct Answer - Option 1 : 340 kg/hr
Concept:
Relationship between steam consumption per hour (m) and the indicated power (IP) is given by:
m = a + b × I.P
Where a and b are constant
Calculation:
Given:
m1 = 280 kg/hr, m2 = 520 kg/hr, (I.P)1 = 15kW, (I.P)2 = 35 kW
Substituting in the above equation
280 = a + b × 15 ----(i)
520 = a + b × 35 ----(ii)
solving equation (i) and (ii) we get
a = 100, b = 12
m = 100 + 12 × I.P
∴ steam consumption when developing 20 kW of power
m = 100 + 12 × 20 = 340 kg/hr