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In case of varactor diode with hyper-abrupt junction the sensitivity (S) value for \(m=-\dfrac{5}{3}\) is
1. 2
2. 3
3. 1
4. \(\dfrac{1}{2}\)

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Correct Answer - Option 2 : 3

Concept:

The sensitivity is defined as:

\(S=\dfrac{1}{m+2}\)

Calculation:

For m = -5 / 3

\(S = \frac{1}{{ - \frac{5}{3} + 2}} = 3\)

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