Question

⊕ and ⊙ are two operators on numbers p and q such that \(p ⊕ q = \frac{p^2 + q^2}{pq}\) and \(p ⊙ q = \frac{p^2}{q}\). If x ⊕ y = 2 ⊙ 2, then x = 
1. y
2. 2 y 
3. \(\frac{3y}{2}\)
4. \(\frac{y}{2}\)

Answer 1

Correct Answer - Option 1 : y

Explanation:

 x ⊕ y = 2 ⊙ 2

\(\frac{{{x^2} + {y^2}}}{{xy}} = \frac{{{2^2}}}{2}\)

x² + y² = 2xy

(x - y)² = 0

x = y