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X is a uniformly distributed random variable that takes value between 0 and 1. The value of E(X3) will be

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Correct Answer - Option 3 : \(\frac{1}{4}\)

Concept:

For uniform distribution:

\({\rm{f}}\left( {\rm{x}} \right) = \frac{1}{{{\rm{b}} - {\rm{a}}}}\) for a < x < b

\({\rm{E}}\left( {{{\rm{X}}^n}} \right) = \mathop \smallint \limits_{0}^1 {{\rm{X}}^n}{\rm{f}}\left( {\rm{X}} \right){\rm{dX}}\)

Calculation:

Given:

a = 0, b = 1,

\({\rm{f}}\left( {\rm{x}} \right) = \frac{1}{{{\rm{b}} - {\rm{a}}}}\)

\({\rm{f}}\left( {\rm{x}} \right) = \frac{1}{{1 - 0}} = 1\)

\(\begin{array}{l} {\rm{E}}\left( {{{\rm{X}}^3}} \right) = \mathop \smallint \limits_{0}^1 {{\rm{X}}^3}{\rm{f}}\left( {\rm{X}} \right){\rm{dX}}\\ = \left[ {\frac{{{{\rm{X}}^4}}}{4}} \right]_{0}^1 = \frac{1}{4} \end{array}\)

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