Correct Answer - Option 3 : 4.4 cm
Concept:
Spacing (S) of reinforcement in slab = \(\frac{{1000}}{{Ast}} \times \frac{\pi }{4}{(ϕ )^2}\)
where ϕ = diameter of bar
Calculation:
Given,
ϕ1 = 10 mm
S1 = 100 mm = 10 cm
ϕ2 = 12 mm
Spacing (S) = \(\frac{{1000}}{{Ast}} \times \frac{\pi }{4}{(ϕ )^2}\)
S ∝ ϕ2 ⟹ \(\frac{{{S_1}}}{{{\phi _1}^2}} = \frac{{{S_2}}}{{{\phi _2}^2}}\)
\({S_2} = {S_1}(\frac{{{\phi _2}^2}}{{{\phi _1}^2}}) = 100 \times \frac{{{{12}^2}}}{{{{10}^2}}}\) = 144 mm = 14.4 cm
As in the Question, it is asked spacing w.r.t. current spacing would be increased by
= S2 - S1 = 14.4 - 10 cm = 4.4 cm