Correct Answer - Option 1 : 200 MPa
Concept:
Equation of pure Bending, \(\frac{M}{I} = \frac{σ }{y} = \frac{E}{R}\) where,
M = Bending moment
σ = Bending stress at a distance y from NA
I = MOI or cross-section about NA
E = Young's modulus
1/R = Curvature
Bending stress, \(\sigma = \frac{E}{R}y\)
Calculation:
Given,
E = 200 GPa = 200000 MPa
B = 120 mm and D = 20 mm
y = D/2 = 10 mm
R = 10 m = 10000 mm
\(\sigma = \frac{E}{R}y = \frac{{200000 \times 10}}{{10000}} = 200MPa\)
The maximum stress induced in the beam is 200 MPa.