Question

In the FORTRAN program

M = 0

DO 100I = 1, 2

DO 200J = 1, 2

M = M + I + J

200 CONTINUE

100 CONTINUE

STOP

END

The value of M, in the end, will be

1. 10
2. 11
3. 12
4. 14

Answer 1

Correct Answer - Option 3 : 12

M = 0, I = 1, J = 1

M = M + I + J

M = 0 + 1 + 1 = 2

M = 2, I = 1, J = 2

M = 2 + 1 + 2 = 5

M = 5, I = 2, J = 1

M = 5 + 2 + 1 = 8

M = 8, I = 2, J = 2

M = 8 + 2 + 2 = 12

So the value of M, in the end, is 12.

• Note – The number 100/200 after the command ‘DO’ gives the label number ending the loop. Since most DO loops operate with an increment of 1 that’s why increment has not been mentioned.