Correct Answer - Option 1 : Path loss is low
A low earth orbit satellite can provide large signal strength at the earth station because path loss is low since low earth orbit (LEO) is the nearest orbit to the earth so path loss is minimum.
Free space path loss \(= {\left( {\frac{{4\pi R}}{\lambda }} \right)^2}\)
Where R is the distance between stations as we can see.
Free path loss ∝ (distance)2
As (distance ↑) → (Pathloss ↑) (Rx signal strength ↓)