Correct Answer - Option 2 : 34 dB
Concept:
Noise figure (NF) and noise factor (F) are measures of degradation of the signal-to-noise ratio (SNR), caused by components in a signal chain.
\(Noise\;Figure = \frac{{{{\left( {SNR} \right)}_{i/p}}}}{{{{\left( {SNR} \right)}_{o/p}}}}\)
(N.F)dB = [(SNR)i/p]dB – [(SNR)o/p]dB
Calculation:
Given:
NF = 2
(SNR)i/p = 37 dB,
N.F(dB) = 10log10(NF)
N.F(dB) = 3 dB
(N.F)dB = [(SNR)i/p]dB – [(SNR)o/p]dB
[(SNR)o/p]dB = 37 dB – 3 dB = 34 dB
