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A three digit number divisible by ten is such that the sum of the digits is 11. When the number is reversed and subtracted from the original, the difference is 495. What is the number?
1. 650
2. 560
3. 740
4. 470

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Correct Answer - Option 2 : 560

Concept:

Any number divisible by 10 has 0 in its units place.

Any three digit number abc in its expanded form is equal to 100a + 10b + c;

Calculation:

Let the three digit number be abc;

Divisible by 10 ⇒ c = 0;

Given abc – cba = 495;

In expanded form, it will be

100a + 10b + c – 100c – 10b – a = 99a -99c

⇒ 99(a – c) = 495 ⇒ a = 5;

Sum of the digits is 11 ⇒ a + b+ c = 11

a = 5, c = 0 ⇒ b = 6;

The final number is 560

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