Correct Answer - Option 2 : 1 : 2
Concept:
Intrinsic Impedance(η):
It is given by \({\rm{\eta }} = \sqrt {\frac{{{\rm{j\omega \mu }}}}{{{\rm{σ }} + {\rm{j\omega \epsilon}}}}} \)
if σ = 0 then
\(η = \sqrt {\frac{μ }{{ϵ}}} \)
where μ = μ0μr and ϵ = ϵ0ϵr
ϵr = relative permittivity
μr = relative permeability
Calculation:
given that
media 1 → εr = 1, μr = 4 and σ = 0
media 2 → εr = 4, μr = 4 and σ = 0
η1 : η2 = \(\sqrt {\frac{μ_1 }{{ϵ_1}}}\): \(\sqrt {\frac{μ_2 }{{ϵ_2}}}\)
η1 : η2 = \(\sqrt {\frac{4}{{1}}}\): \(\sqrt {\frac{4 }{{4}}}\)
η2 : η1 = 1 : 2