Correct Answer - Option 2 : 44.2 m
Concept:
The difference in elevation (∆h) = \(\left( {\frac{{{{\rm{p}}_1} - {{\rm{p}}_2}}}{{{{\rm{P}}_1} \times {{\rm{p}}_2}}}} \right) \times {{\rm{B}}{\rm{f}}}\)
Where,
p1, and p2 = Parallax for the top and bottom respectively, B = length of airbase, and f = focal length of the camera.
Calculation:
Given: Parallax for the top = 52.52 mm, Parallax for the bottom = 48.27 mm, B = 200 m, and F = 120 mm
∆h =
\(\left( {\frac{{52.52 - 48.27}}{{52.52 \times 48.27}}} \right) \times 200 \times 120\;\) = 44.2 m