Correct Answer - Option 1 : 1/3
Solution:
Concept:
P(E) = Number of events/Number of possible outcomes
Calculations:
A pair of unbiased dice is rolled simultaneously
So, the total possible outcomes = 6 × 6 = 36
Total number of events of getting a difference of at least three = (1,4), (1,5), (1,6), (2,5), (2,6), (3,6), (4,1), (5,1), (5,2), (6,1), (6,2), (6,3) = 12
So, the probability of getting a difference of three = 12/36 = 1/3
∴ The probability of getting a difference of at least three is 1/3