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The contents of accumulator after the execution of following instructions will be

MVI A, B7H

ORA A

RAL
1. 6EH
2. 6FH
3. EEH
4. EFH

1 Answer

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Best answer
Correct Answer - Option 1 : 6EH

MVI A, B7H; A → B7 H

ORA A; CY = AC = 0

RAL; Rotate accumulator left with a carry

After RAL, the content of accumulator = 6E H

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