Correct Answer - Option 3 : 3 and 4 only
Concept:
a.b.c.d/NID
Therefore 23 bits are in NID and only 9 bits for Host id.
Explanation:
Last two-byte of IP address is represented in binary
Ethernet: 172.16.2.1/23
Range of IP address: 172.16.00000010.0000000 to 172.16.0000011.11111111
Range of IP address: 172.16.2.0 to 172.16.3.255
First and last IP address is reserved
Valid Host IP address: 172.16.2.1 to 172.16.3.254
Statement 1: 172.16.1.100
It is not valid since it does not fall in the range
Statement 2: 172.16.1.198
It is not valid since it does not fall in the range
Statement 3: 172.16.2.255
It is valid since it does fall in the valid range
Statement 4:172.16.3.0
It is valid since it does fall in the valid range
Hence option 3 is the correct answer.
Important Point:
NID stands for network ID.