Correct Answer - Option 4 : 38.2 lps
Concept:
The theoretical discharge through piston is given by:
\({Q_{th}} = \frac{{ALN}}{{60}}\)
Where,
A = Cross –sectional area
L = Stroke length
N = Speed
D = Dia. Of piston
Calculation:
Given, L = 25 cm, N = 135 rpm, D = 30 cm
\({Q_{th}} = \frac{{\frac{\pi }{4} \times \left( {{{0.3}^2}} \right) \times 0.25 \times 135}}{{60}}\)
Qth = 0.0397 m3/s or 39.7 l/s
We know that,
\({\rm{\% \;slip}} = 1 - {\rm{\;}}\frac{{{{\rm{Q}}_{{\rm{actual}}}}}}{{{{\rm{Q}}_{{\rm{th}}}}}}\)
\(0.04 = 1 - \frac{{{Q_{actual}}}}{{39.7}}\)
∴Qactual = 38.11 l/s