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The starting current of an induction motor is five times the full load current while the full load slip is 8%. Find the ratio of starting torque to full load torque.
1. 8.0
2. 4.0
3. 0.6
4. 2.0

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Correct Answer - Option 4 : 2.0

Concept:

The ratio between the starting torque to full load torque is given by:

\(\frac{{{T}_{st}}}{{{T}_{fl}}}={{s}_{fl}}\times {{\left( \frac{{{I}_{st}}}{{{I}_{fl}}} \right)}^{2}}\)

Where Tst is the starting torque

Tfl is the full load torque

sfl is the slip at full load

Ist is the starting current

Ifl is the rated current

Calculation:

The starting current of a 3-ϕ induction motor is 3 times the rated current. i.e.

Ist = 5 Ifl

Full load slip (sfl) = 8 %

\(\frac{{{T}_{st}}}{{{T}_{fl}}}={0.08}\times {{\left( \frac{{5}}{{1}} \right)}^{2}}\)

= 2.0

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