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Let f(x) = (x - 1)^2 sin(1/(x - 1)) - |x|, if x ≠ 1 f(x) = -1, if x = 1

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Let f(x) = (x - 1)2 sin(1/(x - 1)) - |x|, if x ≠ 1

f(x) = -1, if x = 1

be a real valued function. Then, the set of points where f(x) is not differentiable, is ....

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Given,

Here, f(x) is not differentiable at x = 0 due to | x | .

Thus, f(x) is not differentiable at x = 0

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