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The vapour density of a gas is 8. What would be the volume occupied by 24.0 g of the gas at STP ?

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The vapour density of a gas is 8. What would be the volume occupied by 24.0 g of the gas at STP ?

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Given (Vapour Density) V.D. = 8 

Mol.wt = 2 x V.D.= 2 x 8 = 16

No. of moles in 24.0 g of gas = wt/mol.wt = 24/16 = 1.5 moles

At s.T.P., 1 mole of a gas occupies 22.4 l

1.5 moles (or 24.0 g) of the gas will occupy 

= (22.4 x 1.5)/1 = 33.6 l

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