f(x) = 2x3 – 3x2 [-1, 2]
Global Minimum t f(x) = ?
f (-1) = 2(-1)3 – 3(-1)2 = -2 – 3 ⇒ f (-1) = -5
f (2) = 2(2)3 – 3(2)2 = 16 – 12 ⇒ f (2) = 4
f’(x) = 6x2 – 6x
f’(x) = 0 ⇒ 6x2 – 6x = 0 ⇒ 6x (x - 1) = 0 ⇒ x = 0, 1
So, f (0) = 0
f (1) = 2(1)3 – 3(1)2 ⇒ f (1) = -1
⇒ Key concept: In this question since it is asked for global minimum no. you have to check for all the value which are in the range of [-1, 2].
∴ Global Minimum of f(x) ⇒
f (-1) = -5