Question

The probability that a thermistor randomly picked up from a production unit is defective is 0.1. The probability that out of 10 thermistors randomly picked up, 3 are defective is
1. 0.001
2. 0.057
3. 0.107
4. 0.3

Answer 1

Correct Answer - Option 2 : 0.057

p = 0.1

q = 0.9

n = 10

r = 3

By using binomial distribution,

\(p\left( {x = r} \right) = {n_{{c_r}}}\;{p^r}{q^{n - r}}\)

\(= {10_{{c_3}}}{\left( {0.1} \right)^3}{\left( {0.9} \right)^7} = 0.057\)