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Let-f(x) = ax^2 + bx + c, a ≠ 0 and Δ = b^2 - 4ac. If α + β, α^2 + β^2 and α^3 + β^3 are in GP, then

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Let-f(x) = ax2 + bx + c, a ≠ 0 and Δ = b2 - 4ac. If α + β, α2 + β2 and α3 + β3 are in GP, then

(a) Δ ≠ 0

(b) bΔ = 0

(c) cΔ = 0

(d) bc ≠ 0

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The correct option is (c) cΔ = 0

Explanation:

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